For diode D_1,the forward bias resistance is | vedclass

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(B) From the circuit diagram,$D_1$ and $D_2$ are connected in parallel between $A$ and $B$.$(i)$ If $A$ is at a higher potential,$D_1$ is forward bias

Vedclass · Accepted Answer

$\frac{200}{11} \ \Omega$ and $\frac{200}{7} \ \Omega$

Vedclass · Answer

(B) From the circuit diagram,$D_1$ and $D_2$ are connected in parallel between $A$ and $B$.$(i)$ If $A$ is at a higher potential,$D_1$ is forward biased $(R_{f1} = 20 \ \Omega)$ and $D_2$ is reverse biased $(R_{r2} = 200 \ \Omega)$.The equivalent resistance $R_{eq1} = \frac{R_{f1} 	imes R_{r2}}{R_{f1} + R_{r2}} = \frac{20 	imes 200}{20 + 200} = \frac{4000}{220} = \frac{200}{11} \ \Omega$.$(ii)$ If $B$ is at a higher potential,$D_2$ is forward biased $(R_{f2} = 30 \ \Omega)$ and $D_1$ is reverse biased $(R_{r1} = 600 \ \Omega)$.The equivalent resistance $R_{eq2} = \frac{R_{f2} 	imes R_{r1}}{R_{f2} + R_{r1}} = \frac{30 	imes 600}{30 + 600} = \frac{18000}{630} = \frac{1800}{63} = \frac{200}{7} \ \Omega$.

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