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(B) Let the velocity of the man be $\vec{v} = v \cos	heta \hat{i} + v \sin	heta \hat{j}$,where the mirror is in the $yz$-plane and the normal is alo

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$2v \cos	heta$

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(B) Let the velocity of the man be $\vec{v} = v \cos	heta \hat{i} + v \sin	heta \hat{j}$,where the mirror is in the $yz$-plane and the normal is along the $x$-axis.The velocity of the image $\vec{v}_i$ is given by $\vec{v}_i = -v \cos	heta \hat{i} + v \sin	heta \hat{j}$.The velocity of the image relative to the man is $\vec{v}_{im} = \vec{v}_i - \vec{v}_m = (-v \cos	heta - v \cos	heta) \hat{i} + (v \sin	heta - v \sin	heta) \hat{j} = -2v \cos	heta \hat{i}$.The magnitude of this relative velocity is $|\vec{v}_{im}| = 2v \cos	heta$.

$A$ man moves towards a plane mirror with a velocity $v$ in a direction making an angle $\theta$ with the normal to the mirror. The magnitude of the velocity of the image relative to the man is:

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