The focus and directrix of the parabola {x^2} | vedclass

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Question

(A) The given equation of the parabola is ${x^2} = -8ay$. Comparing this with the standard form ${x^2} = -4Ay$,we get $4A = 8a$,which implies $A = 2a$

Vedclass · Accepted Answer

$(0, -2a)$ and $y = 2a$

Vedclass · Answer

(A) The given equation of the parabola is ${x^2} = -8ay$. Comparing this with the standard form ${x^2} = -4Ay$,we get $4A = 8a$,which implies $A = 2a$. The focus of the parabola ${x^2} = -4Ay$ is $(0, -A)$. Substituting $A = 2a$,the focus is $(0, -2a)$. The equation of the directrix is $y = A$. Substituting $A = 2a$,the directrix is $y = 2a$. Thus,the focus is $(0, -2a)$ and the directrix is $y = 2a$.

The focus and directrix of the parabola ${x^2} = - 8ay$ are

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