Find the value of Relative velocity of any two particles moving in a frame of reference.
Consider there are two particles A and B in a frame of reference and having velocities $\overrightarrow{\mathrm{V}}_{\mathrm{A}}$ and $\vec{V}_{B}$
The velocity of particle$ A$ with respect to $B$ is given by
$\vec{V}_{A B}=\vec{V}_{A}-\vec{V}_{B}$
The velocity of particle B w.r.t. A is given by
$\vec{V}_{B A}=\vec{V}_{B}-\vec{V}_{A}$
Thus, we can write,
$\vec{V}_{A B}=-\vec{V}_{B A} \text { and }\left|\vec{V}_{A B}\right|=\left|\vec{V}_{B A}\right|$
In general If $\mathrm{P}$ and ' $\mathrm{Q}^{\prime}$ are moving along with $\mathrm{X}$
then $\vec{V}_{P Q}=\vec{V} \mathrm{PX}+\vec{V} \times Q$
$\overrightarrow{\mathrm{V}} \mathrm{PQ}=\overrightarrow{\mathrm{V}}_{\mathrm{PX}}-\overrightarrow{\mathrm{V}} \mathrm{QX} \quad \ldots$ (3) $[\because \overrightarrow{\mathrm{V}} \mathrm{XQ}=-\overrightarrow{\mathrm{V}} \mathrm{QX}]$
A particle starts from rest and performing circular motion of constant radius with speed given by $v = \alpha \sqrt x$ where $\alpha$ is a constant and $x$ is the distance covered. The correct graph of magnitude of its tangential acceleration $(a_t)$ and centripetal acceleration $(a_c)$ versus $t$ will be:
The position vector of a particle is given as $\vec r\, = \,({t^2}\, - \,8t\, + \,12)\,\hat i\,\, + \,\,{t^2}\hat j$ The time after which velocity vector and acceleration vector becomes perpendicular to each other is equal to........$sec$
If the position vector of a particle is
$\vec r = - \cos \,t\hat i + \sin \,t\hat j - 18\,t\hat k$
then what is the magnitude of its acceleration ?
The initial velocity of a projectile is $\vec u = (4\hat i + 3\hat j)\,m/s$ it is moving with uniform acceleration $\vec a = (0.4\hat i + 0.3\hat j)\, m/s^2$ The magnitude of its velocity after $10\,s$ is.........$m/s$