Find the value of current $i_1$ for the circuit shown in the figure. (in $, A$)

If the charge on the capacitor is $1 \text{ mC}$ in the given circuit,then $\frac{R_1 R_2}{R_3} = \ldots \ldots \ldots \Omega$.

In a Wheatstone bridge,three resistances $P, Q$ and $R$ are connected in the three arms and the fourth arm is formed by two resistances $S_1$ and $S_2$ connected in parallel. The condition for the bridge to be balanced is

Find the current in the $10\,\Omega$ resistance. The circuit consists of two $5\,V$ batteries with internal resistances of $2\,\Omega$ each,connected in parallel with a $10\,\Omega$ resistor.

What are the advantages of the null-point method in a Wheatstone bridge? What additional measurements would be required to calculate $R_{\text{unknown}}$ by any other method?

Potential difference between $A$ and $B$ is .............. $V$.