Find the value of a,if the distance between t | vedclass

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(B) According to the distance formula,the distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 -

Vedclass · Accepted Answer

$-3$

Vedclass · Answer

(B) According to the distance formula,the distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $A(-3, -14)$ and $B(a, -5)$ with distance $d = 9$.Substituting the values into the formula:$9 = \sqrt{(a - (-3))^2 + (-5 - (-14))^2}$$9 = \sqrt{(a + 3)^2 + (-5 + 14)^2}$$9 = \sqrt{(a + 3)^2 + (9)^2}$Squaring both sides:$81 = (a + 3)^2 + 81$Subtracting $81$ from both sides:$(a + 3)^2 = 0$Taking the square root:$a + 3 = 0$$a = -3$.Thus,the required value of $a$ is $-3$.

Find the value of $a$,if the distance between the points $A(-3, -14)$ and $B(a, -5)$ is $9$ units.

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