Find the roots of the quadratic equation 2x^{ | vedclass

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Question

(B) For the quadratic equation $ax^{2}+bx+c=0$,the roots are given by the quadratic formula $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$.Here,$a=2$,$b=-\s

Vedclass · Accepted Answer

$\frac{\sqrt{5}+\sqrt{21}}{4} , \frac{\sqrt{5}-\sqrt{21}}{4}$

Vedclass · Answer

(B) For the quadratic equation $ax^{2}+bx+c=0$,the roots are given by the quadratic formula $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$.Here,$a=2$,$b=-\sqrt{5}$,and $c=-2$.First,calculate the discriminant $D = b^{2}-4ac$:$D = (-\sqrt{5})^{2} - 4 	imes 2 	imes (-2) = 5 + 16 = 21$.Now,substitute the values into the quadratic formula:$x = \frac{-(-\sqrt{5}) \pm \sqrt{21}}{2 	imes 2} = \frac{\sqrt{5} \pm \sqrt{21}}{4}$.Thus,the roots are $\frac{\sqrt{5}+\sqrt{21}}{4}$ and $\frac{\sqrt{5}-\sqrt{21}}{4}$.

Find the roots of the quadratic equation $2x^{2}-\sqrt{5}x-2=0$ using the quadratic formula.

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