Find the ratio of energy stored in 5,mu F and | vedclass

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(C) In steady state,capacitors act as open circuits. The current $I$ flows through the $5\,\Omega$ and $4\,\Omega$ resistors in series.$I = \frac{V}{R

Vedclass · Accepted Answer

$0.8$

Vedclass · Answer

(C) In steady state,capacitors act as open circuits. The current $I$ flows through the $5\,\Omega$ and $4\,\Omega$ resistors in series.$I = \frac{V}{R_{eq}} = \frac{2}{5+4} = \frac{2}{9} \, A$.Voltage across the $5\,\mu F$ capacitor is the potential difference across the $4\,\Omega$ resistor: $V_{5\mu F} = I 	imes 4 = \frac{2}{9} 	imes 4 = \frac{8}{9} \, V$.Voltage across the $4\,\mu F$ capacitor is the potential difference across the $5\,\Omega$ resistor: $V_{4\mu F} = I 	imes 5 = \frac{2}{9} 	imes 5 = \frac{10}{9} \, V$.Energy stored $U = \frac{1}{2}CV^2$.Ratio $\frac{U_{5\mu F}}{U_{4\mu F}} = \frac{\frac{1}{2} 	imes 5 	imes (\frac{8}{9})^2}{\frac{1}{2} 	imes 4 	imes (\frac{10}{9})^2} = \frac{5 	imes 64}{4 	imes 100} = \frac{320}{400} = 0.8$.

Find the ratio of energy stored in $5\,\mu F$ and $4\,\mu F$ capacitor in the given circuit in steady state.

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