The charge across the capacitor in two differ | vedclass

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(D) From the graph,both circuits reach the same maximum charge $q_{\max}$.Since $q_{\max} = C_1 V_1 = C_2 V_2$,it is clear that both capacitors are ch

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$A$ and $C$ both

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(D) From the graph,both circuits reach the same maximum charge $q_{\max}$.Since $q_{\max} = C_1 V_1 = C_2 V_2$,it is clear that both capacitors are charged to the same magnitude of charge. Thus,statement $A$ is correct.The time constant $	au = RC$ determines the rate of charging. From the graph,circuit $2$ takes more time to reach $q_{\max}$ compared to circuit $1$,implying $	au_2 > 	au_1$,or $R_2 C_2 > R_1 C_1$.Since $q_{\max} = CV$,we have $V = q_{\max} / C$. Because we do not know the individual values of $C_1$ and $C_2$,we cannot determine the relationship between $V_1$ and $V_2$. Therefore,the $emf's$ ($V_1$ and $V_2$) may be different. Thus,statement $C$ is also correct.Since both $A$ and $C$ are correct,the correct option is $D$.

The charge across the capacitor in two different $RC$ circuits $1$ and $2$ are plotted as shown in the figure. Choose the correct statement$(s)$ related to the two circuits.

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