Find the rate law for the reaction,$CHCl_{3(g)} + Cl_{2(g)} \rightarrow CCl_{4(g)} + HCl_{(g)}$ if the order of reaction with respect to $CHCl_{3(g)}$ is $1$ and with respect to $Cl_{2(g)}$ is $1/2$.

  • A
    Rate $= k[CHCl_3][Cl_2]^{1/2}$
  • B
    Rate $= k[CHCl_3]^2[Cl_2]^{1/2}$
  • C
    Rate $= k[CHCl_3]^{3/2}[Cl_2]$
  • D
    Rate $= k[CHCl_3]^{1/2}[Cl_2]$

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