Find the radius of a metal atom in a simple cubic unit cell having an edge length of $334.7 \ pm$. (in $pm$)

The unit cell of an element has an edge length of $5 \mathring{A}$ and a density of $4 \ g \ cm^{-3}$. If its atomic mass is $149 \ g \ mol^{-1}$,identify the crystal structure.

$A$ metal crystallises in a face-centred cubic $(FCC)$ structure with a metallic radius of $\sqrt{2} \ \mathring{A}$. The volume of the unit cell (in $m^{3}$) is:

In a body-centered cubic $(BCC)$ unit cell of a metal,the edge length is $4 \times 10^{-10} \ m$. The diameter of the atom will be:

If the density of a gold $(Au)$ crystal crystallizing in a $ccp$ structure is $19.3 \, g/cm^3$,what will be the radius of the atom? (Given: $Au = 197 \, amu$)

Aluminium crystallises in a face-centred cubic structure, its atomic radius is $125 \text{ pm}$. What is the edge length of the unit cell (in $\text{pm}$)?