Find the number of electrons transferred between two points kept at a potential difference of $20\, V$ if $40\, J$ of work is done.

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Here, potential difference $( V )=20 V ,$ work $( W )=40 J$

We know that

Work $( W )=$ Charge $( Q ) \times$ Potential difference $( V )$

or $\quad 40 J = Q \times 20 V$

or $\quad Q =\frac{40 J }{20 V }=2 C$

No. of electrons $=\frac{2 C }{1.6 \times 10^{-19} C }=1.25 \times 10^{19}$

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