Find the equation of the circle with centre ( | vedclass

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(A) The standard equation of a circle with centre $(h, k)$ and radius $r$ is given by:$(x-h)^{2} + (y-k)^{2} = r^{2}$Given that the centre $(h, k) = (

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$x^{2}+y^{2}-2x-2y=0$

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(A) The standard equation of a circle with centre $(h, k)$ and radius $r$ is given by:$(x-h)^{2} + (y-k)^{2} = r^{2}$Given that the centre $(h, k) = (1, 1)$ and the radius $r = \sqrt{2}$.Substituting these values into the equation:$(x-1)^{2} + (y-1)^{2} = (\sqrt{2})^{2}$Expanding the terms:$(x^{2} - 2x + 1) + (y^{2} - 2y + 1) = 2$Simplifying the equation:$x^{2} + y^{2} - 2x - 2y + 2 = 2$$x^{2} + y^{2} - 2x - 2y = 0$

Find the equation of the circle with centre $(1, 1)$ and radius $\sqrt{2}$.

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