Find the electric field at point $P$ (as shown in figure) on the perpendicular bisector of a uniformly charged thin wire of length $L$ carrying a charge $Q.$ The distance of the point $P$ from the centre of the rod is $a=\frac{\sqrt{3}}{2} L$.

981-794

  • [JEE MAIN 2021]
  • A

    $\frac{\sqrt{3} Q }{4 \pi \varepsilon_{0} L ^{2}}$

  • B

    $\frac{ Q }{3 \pi \varepsilon_{0} L ^{2}}$

  • C

    $\frac{Q}{2 \sqrt{3} \pi \varepsilon_{0} L ^{2}}$

  • D

    $\frac{ Q }{4 \pi \varepsilon_{0} L ^{2}}$

Similar Questions

The electric field intensity at a point in vacuum is equal to

Four charges $q, 2q, -4q$ and $2q$ are placed in order at the four corners of a square of side $b$. The net field at the centre of the square is

For the given figure the direction of electric field at $A$ will be

Is electric field scalar or vector ? Why ?

Figures below show regular hexagons, with charges at the vertices. In which of the following cases the electric field at the centre is not zero