(B) The distance $d$ of a point $P(x, y, z)$ from the origin $O(0, 0, 0)$ is given by the formula: $d = \sqrt{x^2 + y^2 + z^2}$ Given the point $(6, 6

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(B) The distance $d$ of a point $P(x, y, z)$ from the origin $O(0, 0, 0)$ is given by the formula: $d = \sqrt{x^2 + y^2 + z^2}$ Given the point $(6, 6, 7)$,we substitute the values into the formula: $d = \sqrt{6^2 + 6^2 + 7^2}$ $d = \sqrt{36 + 36 + 49}$ $d = \sqrt{121}$ $d = 11$ Thus,the distance from the origin to the point $(6, 6, 7)$ is $11$ units.