The shortest distance of the point (a, b, c) | vedclass

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(B) The coordinates of the point are $P(a, b, c)$.To find the shortest distance from a point $P(a, b, c)$ to the $X-$axis,we consider the projection o

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$\sqrt{b^2 + c^2}$

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(B) The coordinates of the point are $P(a, b, c)$.To find the shortest distance from a point $P(a, b, c)$ to the $X-$axis,we consider the projection of the point onto the $X-$axis.The projection of point $P(a, b, c)$ on the $X-$axis is $P'(a, 0, 0)$.The distance $d$ between $P(a, b, c)$ and $P'(a, 0, 0)$ is given by the distance formula:$d = \sqrt{(a - a)^2 + (b - 0)^2 + (c - 0)^2}$$d = \sqrt{0^2 + b^2 + c^2}$$d = \sqrt{b^2 + c^2}$Therefore,the shortest distance is $\sqrt{b^2 + c^2}$.

The shortest distance of the point $(a, b, c)$ from the $X-$axis is:

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