Find the distance between the points $P(1, -3, 4)$ and $Q(-4, 1, 2)$.

If the centroid of the tetrahedron $OABC$,where $O$ is the origin $(0, 0, 0)$ and $A, B, C$ are given by $(a, 2, 3)$,$(1, b, 2)$,and $(2, 1, c)$ respectively,is $(1, 2, -1)$,then the distance of point $P(a, b, c)$ from the origin is equal to:

From which of the following is the distance of the point $(1, 2, 3)$ equal to $\sqrt{10}$?

If the sum of the squares of the distances of a point from the three coordinate axes is $36$,then its distance from the origin is:

$A$ point is on the $x$-axis. What are its $y$-coordinate and $z$-coordinate?

How far apart are the points $(2,0,0)$ and $(-3,0,0)$?