Easy
Find the derivative of $f$ given by $f(x) = \tan^{-1} x$,assuming it exists.
- A$\frac{1}{1+x^2}$
- B$\frac{1}{1-x^2}$
- C$\frac{-1}{1+x^2}$
- D$\frac{1}{\sqrt{1-x^2}}$
Explore More
Similar Questions
Find the value of $k$ if $\frac{d}{d x}\left\{\frac{2}{\sqrt{2+\sqrt{2+\sqrt{2+2 \cos (4 x)}}}}\right\} = k \sec \left(\frac{x}{2}\right) \tan \left(\frac{x}{2}\right)$
DifficultAP EAMCET 2021
View SolutionIf $f: R \rightarrow R$ is an even function having derivatives of all orders,then which of the following is an odd function?
If $y=\tan ^{-1}(\sin \sqrt{x})+\operatorname{cosec}^{-1}\left(e^{2 x+1}\right)$,then $\frac{d y}{d x}=$
Differentiate with respect to $x$,the following function:
$e^{\sec ^{2} x}+3 \cos ^{-1} x$
$e^{\sec ^{2} x}+3 \cos ^{-1} x$
Medium
View SolutionIf $f(t) = \frac{t}{2} + \frac{1}{4} \log(2t - 1)$,then $f^{\prime}\left(\frac{t+1}{2t+1}\right) = $
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo