Find the cost of laying grass in a triangular | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The sides of the triangular field are $a = 50 \, m$,$b = 65 \, m$,and $c = 65 \, m$.First,we calculate the semi-perimeter $s$:$s = \frac{a + b + c

Vedclass · Accepted Answer

$10500$

Vedclass · Answer

(C) The sides of the triangular field are $a = 50 \, m$,$b = 65 \, m$,and $c = 65 \, m$.First,we calculate the semi-perimeter $s$:$s = \frac{a + b + c}{2} = \frac{50 + 65 + 65}{2} = \frac{180}{2} = 90 \, m$.Using Heron's formula,the area of the triangle is:$	ext{Area} = \sqrt{s(s-a)(s-b)(s-c)}$$= \sqrt{90(90-50)(90-65)(90-65)}$$= \sqrt{90 	imes 40 	imes 25 	imes 25}$$= \sqrt{3600 	imes 625} = 60 	imes 25 = 1500 \, m^2$.The cost of laying grass is given by the product of the area and the rate:$	ext{Cost} = 1500 \, m^2 	imes 7 \, Rs/m^2 = 10,500 \, Rs$.

Find the cost of laying grass in a triangular field of sides $50 \, m$,$65 \, m$,and $65 \, m$ at the rate of $Rs \, 7$ per $m^2$ (in $Rs$).

Similar Questions

The perimeter of an isosceles triangle is $32 \, cm$. The ratio of the equal side to its base is $3: 2$. Find the area of the triangle.

The base of a right triangle is $8 \, cm$ and its hypotenuse is $10 \, cm$. Its area will be (in $cm^2$):

$A$ field is shaped like an equilateral triangle. Its length is $120 \, m$ on each side. Calculate its area using Heron's formula.

Find the area of the triangular field with the length of the sides $360 \, m$,$450 \, m$,and $450 \, m$.

The perimeter of a triangular field is $420\, m$ and its sides are in the ratio $6: 7: 8$. Find the area of the triangular field (in $m^2$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module