The base of a right triangle is 8 , cm and it | vedclass

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(A) Let the right triangle be $	riangle ABC$ where $\angle B = 90^{\circ}$.Given: Base $BC = 8 \, cm$ and hypotenuse $AC = 10 \, cm$.According to the

Vedclass · Accepted Answer

$24$

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(A) Let the right triangle be $	riangle ABC$ where $\angle B = 90^{\circ}$.Given: Base $BC = 8 \, cm$ and hypotenuse $AC = 10 \, cm$.According to the Pythagorean theorem: $AC^2 = AB^2 + BC^2$.Substituting the values: $10^2 = AB^2 + 8^2$.$100 = AB^2 + 64$.$AB^2 = 100 - 64 = 36$.$AB = \sqrt{36} = 6 \, cm$.The area of a right triangle is given by the formula: $	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$.$	ext{Area} = \frac{1}{2} 	imes 8 	imes 6 = 24 \, cm^2$.

The base of a right triangle is $8 \, cm$ and its hypotenuse is $10 \, cm$. Its area will be (in $cm^2$):

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