Find the coordinates of the points which divide the line segment joining $A (-2, 2)$ and $B (2, 8)$ into four equal parts.

(N/A) Let the points dividing the line segment $AB$ into four equal parts be $X, Y, Z$. These points divide the segment in the ratios $1:3, 1:1, 3:1$ respectively.
Coordinates of $X = \left(\frac{1 \times 2 + 3 \times (-2)}{1 + 3}, \frac{1 \times 8 + 3 \times 2}{1 + 3}\right) = \left(\frac{2 - 6}{4}, \frac{8 + 6}{4}\right) = \left(-1, \frac{14}{4}\right) = \left(-1, 3.5\right)$.
Coordinates of $Y$ (midpoint of $AB$) $= \left(\frac{-2 + 2}{2}, \frac{2 + 8}{2}\right) = \left(0, \frac{10}{2}\right) = (0, 5)$.
Coordinates of $Z = \left(\frac{3 \times 2 + 1 \times (-2)}{3 + 1}, \frac{3 \times 8 + 1 \times 2}{3 + 1}\right) = \left(\frac{6 - 2}{4}, \frac{24 + 2}{4}\right) = \left(\frac{4}{4}, \frac{26}{4}\right) = (1, 6.5)$.