Find the coordinates of the point which divid | vedclass

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(C) Let the points be $A(x_1, y_1) = (3, 2)$ and $B(x_2, y_2) = (-2, -5)$.Let the point $P(x, y)$ divide the segment $\overline{AB}$ in the ratio $m:n

Vedclass · Accepted Answer

$\left(0, -2.2\right)$

Vedclass · Answer

(C) Let the points be $A(x_1, y_1) = (3, 2)$ and $B(x_2, y_2) = (-2, -5)$.Let the point $P(x, y)$ divide the segment $\overline{AB}$ in the ratio $m:n = 3:2$ starting from $A$.Using the section formula,the coordinates of $P$ are given by:$x = \frac{mx_2 + nx_1}{m+n} = \frac{3(-2) + 2(3)}{3+2} = \frac{-6 + 6}{5} = \frac{0}{5} = 0$$y = \frac{my_2 + ny_1}{m+n} = \frac{3(-5) + 2(2)}{3+2} = \frac{-15 + 4}{5} = \frac{-11}{5} = -2.2$Thus,the coordinates of the point are $(0, -2.2)$.

Find the coordinates of the point which divides $\overline{AB}$ in the ratio $3:2$ from $A$. The coordinates of $A$ and $B$ are $(3, 2)$ and $(-2, -5)$ respectively.

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