(A) The rate of reaction is expressed as: $Rate = -\frac{1}{2} \frac{\Delta[NO_2]}{\Delta t} = \frac{1}{2} \frac{\Delta[NO]}{\Delta t} = \frac{\Delta[

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$\frac{x}{2} \ mol \ dm^{-3} \ s^{-1}$

(A) The rate of reaction is expressed as: $Rate = -\frac{1}{2} \frac{\Delta[NO_2]}{\Delta t} = \frac{1}{2} \frac{\Delta[NO]}{\Delta t} = \frac{\Delta[O_2]}{\Delta t}$ Given that the rate of disappearance of $NO_2$ is $-\frac{\Delta[NO_2]}{\Delta t} = x \ mol \ dm^{-3} \ s^{-1}$. Substituting this into the rate expression: $\frac{\Delta[O_2]}{\Delta t} = \frac{1}{2} \left( -\frac{\Delta[NO_2]}{\Delta t} \right)$ $\frac{\Delta[O_2]}{\Delta t} = \frac{1}{2} \times x = \frac{x}{2} \ mol \ dm^{-3} \ s^{-1}$

Class 12 Chemistry Chemical Kinetics Rate of a reaction

Medium

Find the average rate of formation of $O_{2(g)}$ in the following reaction:
$2 NO_{2(g)} \rightarrow 2 NO_{(g)} + O_{2(g)}$
Given that $\left[-\frac{\Delta[NO_2]}{\Delta t}\right] = x \ mol \ dm^{-3} \ s^{-1}$

MHT CET 2023 All MHT CET

A
$\frac{x}{2} \ mol \ dm^{-3} \ s^{-1}$
B
$x \ mol \ dm^{-3} \ s^{-1}$
C
$2x \ mol \ dm^{-3} \ s^{-1}$
D
$4x \ mol \ dm^{-3} \ s^{-1}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

Rate of a reaction

Previous Year

MHT CET 2023 Paper All MHT CET years →

In a pseudo first order hydrolysis of ester in water,the following results were obtained:

$t \ (s)$ $0$ $30$ $60$ $90$

$[\text{Ester}] \ (mol \ L^{-1})$ $0.55$ $0.31$ $0.17$ $0.085$

What will be the average rate of reaction between the time interval $30 \ s$ to $60 \ s$?

Medium

View Solution

If the rate of disappearance of $N_2O_5$ in the following reaction is $1.2 \times 10^{-5} \ mol \ L^{-1} \ s^{-1}$,the rate of production of $NO_2$ in $mol \ L^{-1} \ s^{-1}$ is:
$2N_2O_{5(g)} \longrightarrow 4NO_{2(g)} + O_{2(g)}$

EasyAP EAMCET 2016

View Solution

For the reaction $2N_2O_5(g) \rightleftharpoons 4NO_2(g) + O_2(g)$ in a closed vessel,the concentration of $NO_2$ increases by $2.0 \times 10^{-2} \ mol \ L^{-1}$ in $5 \ s$. Calculate the rate of change of concentration of $N_2O_5$.

Medium

View Solution

The rate of a reaction that does not involve gases is not dependent on:

Easy

View Solution

In the following reaction $3A \to B + 2C$,the initial concentration of $A$ is $8\,mol\,L^{-1}$. After $10\,min$,it becomes $5\,mol\,L^{-1}$. Find the rate of reaction in $mol\,L^{-1}\,min^{-1}$.

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$t \ (s)$	$0$	$30$	$60$	$90$
$[\text{Ester}] \ (mol \ L^{-1})$	$0.55$	$0.31$	$0.17$	$0.085$

Find the average rate of formation of $O_{2(g)}$ in the following reaction: $2 NO_{2(g)} \rightarrow 2 NO_{(g)} + O_{2(g)}$ Given that $\left[-\frac{\Delta[NO_2]}{\Delta t}\right] = x \ mol \ dm^{-3} \ s^{-1}$

Similar Questions

In a pseudo first order hydrolysis of ester in water,the following results were obtained: $t \ (s)$ $0$ $30$ $60$ $90$ $[\text{Ester}] \ (mol \ L^{-1})$ $0.55$ $0.31$ $0.17$ $0.085$ What will be the average rate of reaction between the time interval $30 \ s$ to $60 \ s$?

If the rate of disappearance of $N_2O_5$ in the following reaction is $1.2 \times 10^{-5} \ mol \ L^{-1} \ s^{-1}$,the rate of production of $NO_2$ in $mol \ L^{-1} \ s^{-1}$ is:$2N_2O_{5(g)} \longrightarrow 4NO_{2(g)} + O_{2(g)}$

For the reaction $2N_2O_5(g) \rightleftharpoons 4NO_2(g) + O_2(g)$ in a closed vessel,the concentration of $NO_2$ increases by $2.0 \times 10^{-2} \ mol \ L^{-1}$ in $5 \ s$. Calculate the rate of change of concentration of $N_2O_5$.

The rate of a reaction that does not involve gases is not dependent on:

In the following reaction $3A \to B + 2C$,the initial concentration of $A$ is $8\,mol\,L^{-1}$. After $10\,min$,it becomes $5\,mol\,L^{-1}$. Find the rate of reaction in $mol\,L^{-1}\,min^{-1}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Find the average rate of formation of $O_{2(g)}$ in the following reaction:
$2 NO_{2(g)} \rightarrow 2 NO_{(g)} + O_{2(g)}$
Given that $\left[-\frac{\Delta[NO_2]}{\Delta t}\right] = x \ mol \ dm^{-3} \ s^{-1}$

In a pseudo first order hydrolysis of ester in water,the following results were obtained:

$t \ (s)$ $0$ $30$ $60$ $90$

$[\text{Ester}] \ (mol \ L^{-1})$ $0.55$ $0.31$ $0.17$ $0.085$

What will be the average rate of reaction between the time interval $30 \ s$ to $60 \ s$?

If the rate of disappearance of $N_2O_5$ in the following reaction is $1.2 \times 10^{-5} \ mol \ L^{-1} \ s^{-1}$,the rate of production of $NO_2$ in $mol \ L^{-1} \ s^{-1}$ is:
$2N_2O_{5(g)} \longrightarrow 4NO_{2(g)} + O_{2(g)}$