Find the angle of deviation for the given dia | vedclass

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Question

(C) The angle of incidence $i$ is the angle between the incident ray and the normal. From the diagram,the angle between the incident ray and the mirro

Vedclass · Accepted Answer

$180^{\circ} - 2	heta$ is incorrect,the correct answer is $180^{\circ} - 2i$. Since $i = 90^{\circ} - 	heta$,the deviation $\delta = 180^{\circ} - 2(90^{\circ} - 	heta) = 2	heta$.

Vedclass · Answer

(C) The angle of incidence $i$ is the angle between the incident ray and the normal. From the diagram,the angle between the incident ray and the mirror surface is $	heta$. Since the normal is perpendicular to the mirror,we have $i + 	heta = 90^{\circ}$,which means $i = 90^{\circ} - 	heta$.The formula for the angle of deviation $\delta$ produced by a plane mirror is $\delta = 180^{\circ} - 2i$.Substituting the value of $i$ into the formula:$\delta = 180^{\circ} - 2(90^{\circ} - 	heta)$$\delta = 180^{\circ} - 180^{\circ} + 2	heta$$\delta = 2	heta$.

Find the angle of deviation for the given diagram.

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