Find the HCF and LCM of the following pairs o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Step $1$: Prime factorization of $26$ and $91$.$26 = 2 	imes 13$$91 = 7 	imes 13$Step $2$: Find $HCF$ and $LCM$.$HCF = 	ext{Product of the smal

Vedclass · Accepted Answer

$HCF = 13, LCM = 182; 2366 = 2366$

Vedclass · Answer

(A) Step $1$: Prime factorization of $26$ and $91$.$26 = 2 	imes 13$$91 = 7 	imes 13$Step $2$: Find $HCF$ and $LCM$.$HCF = 	ext{Product of the smallest power of each common prime factor} = 13$.$LCM = 	ext{Product of the greatest power of each prime factor involved} = 2 	imes 7 	imes 13 = 182$.Step $3$: Verify the relationship $HCF 	imes LCM = 	ext{Product of the two numbers}$.$HCF 	imes LCM = 13 	imes 182 = 2366$.$	ext{Product of the two numbers} = 26 	imes 91 = 2366$.Since $2366 = 2366$, the relationship is verified.

$Q.1.$ $HCF$ of $8$ and $6$	$A. 49$
$Q.2.$ $LCM$ of $(26, 91)$	$B. 182$
	$C. 2$

Find the $HCF$ and $LCM$ of the following pairs of integers and verify that $HCF \times LCM = \text{product of the two numbers}: 26$ and $91$.

Similar Questions

For the polynomial $p(x) = x^2 - 4x + 3$,the value of $\alpha + \beta$ is . . . . . . .

Match the following items:
$Q.1.$ $HCF$ of $8$ and $6$ $A. 49$
$Q.2.$ $LCM$ of $(26, 91)$ $B. 182$
$C. 2$

$\pi$ is a . . . . . . type of number. (Rational,Irrational,Whole number)

For two consecutive positive integers $a$ and $b$,what is the value of $\text{HCF}(a, b) \times \text{LCM}(a, b)$?

The Greatest Common Divisor $(GCD)$ of $20 a^{2} b$ and $30 a b^{2}$ is $10 a^{2} b^{2}$. State whether this statement is True or False.

Vedclass Test Series

Exam Paper Generator

Online Exam Module