Find the LCM and HCF of the following pairs o | vedclass

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(B) First,find the prime factorization of the given numbers:$510 = 2 	imes 3 	imes 5 	imes 17$$92 = 2^2 	imes 23 = 2 	imes 2 	imes 23$To find th

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$46920$

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(B) First,find the prime factorization of the given numbers:$510 = 2 	imes 3 	imes 5 	imes 17$$92 = 2^2 	imes 23 = 2 	imes 2 	imes 23$To find the $HCF$,take the product of the smallest power of each common prime factor:$HCF = 2^1 = 2$To find the $LCM$,take the product of the highest power of each prime factor involved:$LCM = 2^2 	imes 3 	imes 5 	imes 17 	imes 23 = 4 	imes 3 	imes 5 	imes 17 	imes 23 = 23460$Now,verify the relationship:Product of the two numbers $= 510 	imes 92 = 46920$$HCF 	imes LCM = 2 	imes 23460 = 46920$Since $46920 = 46920$,the relationship $LCM 	imes HCF =$ product of the two numbers is verified.

Find the $LCM$ and $HCF$ of the following pairs of integers and verify that $LCM \times HCF =$ product of the two numbers $510$ and $92$.

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