Find the missing information from the following reactions:
$(i)$ $CH_3COOH \rightarrow[\Delta]{H_2SO_4/P_2O_5} ?$
$(ii)$ $? + CH_3OH \rightleftharpoons[H^{+}]{} CH_3COOCH_3 + H_2O$
$(iii)$ $3 CH_3COOH + PCl_3 \rightarrow 3 CH_3COCl + ?$
$(iv)$ $CH_3COOH + PCl_5 \rightarrow CH_3COCl + ? + HCl$
$(v)$ $C_6H_5COONa \rightarrow{?} C_6H_6$
$(vi)$ $CH_3CH_2COOH \rightarrow{\text{excess } Br_2 + \text{Red } P} ? + ?$
$(vii)$ $CH_3CH_2COOH \rightarrow{?} CH_3CH_2CH_2OH$
$(viii)$ $C_6H_5COOH \rightarrow{\text{anhydrous } AlCl_3, CH_3Cl \text{ or } CH_3COCl} ?$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $(i)$ $(CH_3CO)_2O$ (Ethanoic anhydride)
$(ii)$ $CH_3COOH$ (Ethanoic acid)
$(iii)$ $H_3PO_3$ (Phosphorous acid)
$(iv)$ $POCl_3$ (Phosphorous oxychloride)
$(v)$ $\text{Sodalime } (NaOH + CaO, 3:1) + \Delta$
$(vi)$ $CH_3CHBrCOOH + CH_3CBr_2COOH$ (Hell-Volhard-Zelinsky reaction)
$(vii)$ $LiAlH_4$ or $B_2H_6$ followed by $H_3O^{+}$
$(viii)$ No reaction (Carboxylic acid group is deactivating and forms a complex with $AlCl_3$).

Explore More

Similar Questions

Hydrolysis of an ester gives a carboxylic acid which on Kolbe's electrolysis yields ethane. The ester is

Difficult
View Solution

What is the final product $(B)$ of this sequence?

Difficult
View Solution

The increasing order of the acidity of the following carboxylic acids is:

An unknown compound $(A)$ (molar mass $= 180$) on acylation gives a product (molar mass $= 390$). Find the number of hydroxyl group present in compound $(A)$.

Identify the final product in the following reaction:
$CH_3-CH(OH)-COOH \xrightarrow{\Delta} \text{Product}$

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo