Find all the angles of an equilateral triangl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In an equilateral triangle,all three sides are equal,i.e.,$AB = BC = AC$.
Since the angles opposite to equal sides of a triangle are equal,we hav

Vedclass · Accepted Answer

$60^{\circ},60^{\circ},60^{\circ}$

Vedclass · Answer

(A) In an equilateral triangle,all three sides are equal,i.e.,$AB = BC = AC$.
Since the angles opposite to equal sides of a triangle are equal,we have $\angle A = \angle B = \angle C$.
Let each angle be $x$.
By the angle sum property of a triangle,the sum of all interior angles is $180^{\circ}$.
Therefore,$\angle A + \angle B + \angle C = 180^{\circ}$.
$x + x + x = 180^{\circ}$.
$3x = 180^{\circ}$.
$x = \frac{180^{\circ}}{3} = 60^{\circ}$.
Thus,all the angles of an equilateral triangle are $60^{\circ}, 60^{\circ}, 60^{\circ}$.

Find all the angles of an equilateral triangle.

Similar Questions

In $\Delta ABC$,the bisectors of $\angle B$ and $\angle C$ intersect at $P$. $A$ line drawn through $P$ and parallel to $BC$ intersects $AB$ at $X$ and $AC$ at $Y$. Prove that $XY = XB + YC$.

$\angle ABD$ and $\angle ACE$ are exterior angles of $\Delta ABC$. If $\angle ABD > \angle ACE$,then prove that $AC > AB$.

If $\Delta PRQ \cong \Delta ZXY,$ then in $\Delta XYZ,$ which angle is equal to $\angle R$?

In $\triangle ABC$,$AB = AC$ and $\angle B = 50^{\circ}$. Then $\angle C$ is equal to (in $^{\circ}$)

$P$ is a point on the bisector of $\angle ABC$. If the line through $P$,parallel to $BA$,meets $BC$ at $Q$,prove that $\triangle BPQ$ is an isosceles triangle.

Vedclass Test Series

Exam Paper Generator

Online Exam Module