Find $p(0)$, $p(1)$ and $p(2)$ for of the following polynomials : $p(x)=x^{3}$
Find $p(0)$, $p(1)$ and $p(2)$ for of the following polynomials : $p(x)=x^{3}$
$p(x)=x^{3}$
$\because $ $p(x)=x^{3}=(x)^{3}$
$\therefore$ $p(0)=(0)^{3}=0$
$p(1)=(1)^{3}=1$
$p(2)=(2)^{3}=8$ $[\because \,\,2 \times 2 \times 2=8]$
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