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Question

(A) To solve the expression $\sqrt{2} \cdot \sqrt{3} \cdot \sqrt{6}$,we use the property of radicals $\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$.Firs

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) To solve the expression $\sqrt{2} \cdot \sqrt{3} \cdot \sqrt{6}$,we use the property of radicals $\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$.First,multiply the terms inside the square roots: $\sqrt{2} \cdot \sqrt{3} = \sqrt{2 \cdot 3} = \sqrt{6}$.Now,substitute this back into the original expression: $\sqrt{6} \cdot \sqrt{6}$.Using the property $\sqrt{a} \cdot \sqrt{a} = a$,we get $\sqrt{6} \cdot \sqrt{6} = 6$.Therefore,the correct answer is $6$.

Fill in the blanks to make the following statement true: $\sqrt{2} \cdot \sqrt{3} \cdot \sqrt{6} = \dots$

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