Fill in the blanks to make the following statement true: $\sqrt{7}$ is a/an $\ldots \ldots \ldots$ number.
(IRRATIONAL) number is called irrational if it cannot be written in the form $\frac{p}{q}$,where $p$ and $q$ are integers and $q \neq 0$. Since $7$ is not a perfect square,its square root,$\sqrt{7}$,is an irrational number.
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