The figure shows three points A,B,and C in a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. In a uniform electric field,the potential does not change along a direction perpendicular to the field lines. Since $AB$ is perpendicular to

Vedclass · Accepted Answer

$V_A = V_B > V_C$

Vedclass · Answer

(B) $1$. In a uniform electric field,the potential does not change along a direction perpendicular to the field lines. Since $AB$ is perpendicular to the electric field lines,the potential at $A$ is equal to the potential at $B$,i.e.,$V_A = V_B$.$2$. The electric potential decreases in the direction of the electric field. Since $BC$ is parallel to the electric field lines and points in the direction of the field,the potential at $C$ is less than the potential at $B$,i.e.,$V_B > V_C$.$3$. Combining these two results,we get $V_A = V_B > V_C$.

Similar Questions

Which of the following statements is not true?

The figure shows a family of parallel equipotential surfaces and four paths along which an electron is made to move from one surface to another.
$(I)$ What is the direction of the electric field?
$(II)$ Rank the paths according to the magnitude of work done,greatest first.

$A$ uniform electric field of magnitude $E = 100 \ V/m$ is directed along the line $y = x + 3$. Find the potential difference $V_A - V_B$ between points $A(3, 1)$ and $B(1, 3)$.

Draw an equipotential surface for a point charge.

The equation of an equipotential line in an electric field is $y = 2x$. The electric field strength vector at $(1, 2)$ may be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module