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(D) According to Lenz's Law,the induced current will flow in a direction that opposes the change in magnetic flux. Since the inward magnetic field is

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All of the above

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(D) According to Lenz's Law,the induced current will flow in a direction that opposes the change in magnetic flux. Since the inward magnetic field is decreasing,the magnetic flux through the loops is decreasing. To oppose this decrease,the induced magnetic field must be in the same direction as the original field (inward). By the right-hand thumb rule,an inward magnetic field is produced by a clockwise current. Therefore,the induced current in both the outer loop (containing $P$) and the inner loop (containing $Q$) will be clockwise. At point $R$,which lies on the radial connector between the two loops,the current flows in a closed path,and the symmetry of the induced electric field ensures that the net current flow is consistent with the clockwise direction in the loops. Thus,all the given statements are correct.

Column $I$	Column $II$
$(A)$ $A$ charged capacitor is connected to the ends of the wire	$(p)$ $A$ constant current flows through the wire
$(B)$ The wire is moved perpendicular to its length with a constant velocity in a uniform magnetic field perpendicular to the plane of motion	$(q)$ Thermal energy is generated in the wire
$(C)$ The wire is placed in a constant electric field that has a direction along the length of the wire	$(r)$ $A$ constant potential difference develops between the ends of the wire
$(D)$ $A$ battery of constant emf is connected to the ends of the wire	$(s)$ Charges of constant magnitude appear at the ends of the wire

The figure shows a planar conductor located in a magnetic field directed inward,normal to the plane of the figure. The magnetic field starts diminishing. Then the induced current:

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