Factorise the following:

$25 x^{2}+16 y^{2}+4 z^{2}-40 x y+16 y z-20 x z$

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$25 x^{2}+16 y^{2}+4 z^{2}-40 x y+16 y z-20 x z$

$=(-5 x)^{2}+(4 y)^{2}+(2 z)^{2}+2 \cdot(-5 x)(4 y)+2(4 y)(2 z)+2(2 z)(-5 x)$

$=(-5 x+4 y+2 z)^{2}$

Similar Questions

Factorise

$27 x^{3}-y^{3}+64 z^{3}+36 x y z$

Without actually calculating the cubes, find the value of each of the following

$\left(\frac{1}{2}\right)^{3}+\left(\frac{1}{3}\right)^{3}-\left(\frac{5}{6}\right)^{3}$

$x+1$ is a factor of the polynomial

If $x+2$ is a factor of $x^{3}+a x^{2}-x+30,$ find the value of $a$.

Evaluate

$(98)^{2}$