Factorise :
$x^{3}-6 x^{2}+11 x-6$
Without actually calculating the cubes, find the value of each of the following
$\left(\frac{1}{2}\right)^{3}+\left(\frac{1}{3}\right)^{3}-\left(\frac{5}{6}\right)^{3}$
From the following polynomials find out which of them has $(x-1)$ as a factor
$x^{3}+6 x^{2}-9 x-14$
If $(5 x-3)^{2}=25 x^{2}+k x+9,$ then find $k$
Find the value of the polynomial $x^{2}-7 x+12$ at.
$x=1$