Factorise : 8 x^{3}+y^{3}+27 z^{3}-18 x y z | vedclass

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Question

Here, we have

$8 x^{3}+y^{3}+27 z^{3}-18 x y z$

$=(2 x)^{3}+y^{3}+(3 z)^{3}-3(2 x)(y)(3 z)$

$=(2 x+y+3 z)\left[(2 x)^{2}+y^{2}+(3 z)^{2}-(2 x

Vedclass · Accepted Answer

Vedclass · Answer

Here, we have

$8 x^{3}+y^{3}+27 z^{3}-18 x y z$

$=(2 x)^{3}+y^{3}+(3 z)^{3}-3(2 x)(y)(3 z)$

$=(2 x+y+3 z)\left[(2 x)^{2}+y^{2}+(3 z)^{2}-(2 x)(y)-(y)(3 z)-(2 x)(3 z)\right]$

$=(2 x+y+3 z)\left(4 x^{2}+y^{2}+9 z^{2}-2 x y-3 y z-6 x z\right)$

Factorise $: 8 x^{3}+y^{3}+27 z^{3}-18 x y z$

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