Factorise : $49 a^{2}+70 a b+25 b^{2}$
Factorise : $49 a^{2}+70 a b+25 b^{2}$
Here you can see that
$49 a^{2}=(7 a)^{2}, 25 b^{2}=(5 b)^{2}, 70 a b=2(7 a)(5 b)$
Comparing the given expression with $x^{2}+2 x y+y^{2},$ we observe that $x=7 a$ and $y=5 b$ Using Identity $I$, we get
$49 a^{2}+70 a b+25 b^{2}=(7 a+5 b)^{2}=(7 a+5 b)(7 a+5 b)$
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