Express the number 3825 as a product of its p | vedclass

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(B) To find the prime factors of $3825$,we perform successive division by prime numbers:$1$. Since the last digit is $5$,it is divisible by $5$: $3825

Vedclass · Accepted Answer

$3^2 	imes 5^2 	imes 17$

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(B) To find the prime factors of $3825$,we perform successive division by prime numbers:$1$. Since the last digit is $5$,it is divisible by $5$: $3825 \div 5 = 765$.$2$. $765$ is also divisible by $5$: $765 \div 5 = 153$.$3$. Now,check for $3$: The sum of digits of $153$ is $1+5+3 = 9$,which is divisible by $3$. So,$153 \div 3 = 51$.$4$. $51$ is divisible by $3$: $51 \div 3 = 17$.$5$. $17$ is a prime number,so $17 \div 17 = 1$.Thus,the prime factorization is $3825 = 3 	imes 3 	imes 5 	imes 5 	imes 17 = 3^2 	imes 5^2 	imes 17$.

Express the number $3825$ as a product of its prime factors.

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