Explain orbital magnetic moment and spin magnetic moment.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Any charge in uniform circular motion has an associated magnetic moment given by the expression:
$\mu_{l} = \frac{e}{2m_{e}}(l)$
This dipole moment is known as the orbital magnetic moment. Its magnitude is related to the Bohr magneton,which has a value of $9.27 \times 10^{-24} \text{ A m}^2$.
In addition to the orbital magnetic moment,the electron possesses an intrinsic magnetic moment,which has the same numerical value of $9.27 \times 10^{-24} \text{ A m}^2$. This is called the spin magnetic moment.
It is important to note that this does not imply the electron is physically spinning. The electron is an elementary particle and does not have an axis to rotate around like a top or the Earth.

Explore More

Similar Questions

The angle made by the orbital angular momentum of an electron with the direction of its orbital magnetic moment is: (in $^{\circ}$)

What is the magnetic moment of an orbiting electron in a simple hydrogen atom? Assume $e=$ charge of electron,$m_e=$ mass of electron,and $\vec{L}=$ orbital angular momentum of the electron.

The magnetic moment of an electron $(e)$ revolving in an orbit around a nucleus with an orbital angular momentum $\vec{L}$ is given by:

What is orbital magnetic moment? And what is intrinsic magnetic moment?

Difficult
View Solution

An electron moving around the nucleus with an angular momentum $L$ has a magnetic moment ( $e=$ charge on electron,$m=$ mass of electron )

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo