The angle made by the orbital angular momentum of an electron with the direction of its orbital magnetic moment is: (in $^{\circ}$)

What is the magnetic moment of an orbiting electron in a simple hydrogen atom? Assume $e=$ charge of electron,$m_e=$ mass of electron,and $\vec{L}=$ orbital angular momentum of the electron.

$A$ proton moves on a circular path with a constant angular speed. What is the correct relation between its magnetic moment $\vec{M}$ and angular momentum $\vec{L}$?

An electron moving around the nucleus with an angular momentum $L$ has a magnetic moment ( $e=$ charge on electron,$m=$ mass of electron )

Define Bohr magneton using Bohr's first hypothesis.

The ratio of angular momentum $\overrightarrow{L}$ of an electron to the magnetic dipole moment $\overrightarrow{m}_{\text{orb}}$ is (where $m$ is the mass of the electron and $e$ is the charge on the electron).