Explain the mobility of a charge carrier in a conductor and derive its equation.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Mobility $(\mu)$ is defined as the magnitude of the drift velocity $(v_d)$ per unit electric field $(E)$ applied across the conductor.
Mathematically, $\mu = \frac{|v_d|}{E}$.
Since the drift velocity is given by $v_d = \frac{eE\tau}{m}$, where $e$ is the charge, $\tau$ is the relaxation time, and $m$ is the mass of the carrier, substituting this into the mobility equation gives $\mu = \frac{e\tau}{m}$.
$SI$ unit: $\frac{m/s}{V/m} = m^2 V^{-1} s^{-1}$.
Dimensional formula: $[M^{-1} L^0 T^2 A^1]$.

Explore More

Similar Questions

When there is an electric current through a conducting wire along its length,then an electric field must exist

Two identical conductors are kept at the same temperature. If the ratio of the potential difference across them is $1 : 2$,what will be the ratio of their drift velocities?

$A$ wire of non-uniform cross-section is carrying a steady current. Along the wire,

In the presence of an electric field,is the path of a free electron between two successive collisions a straight line?

Explain the drift of electrons and drift velocity. Derive the equation for electric current in terms of the cross-sectional area of a conductor.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo