(C) Given equations are:$x + y = 2$ $(i)$$2x + 2y = 3$ $(ii)$From equation $(ii)$,we can factor out $2$:$2(x + y) = 3$$x + y = \frac{3}{2} = 1.5$Now

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(C) Given equations are:$x + y = 2$ $(i)$$2x + 2y = 3$ $(ii)$From equation $(ii)$,we can factor out $2$:$2(x + y) = 3$$x + y = \frac{3}{2} = 1.5$Now,compare this with equation $(i)$:$x + y = 2$ and $x + y = 1.5$Since $2 \neq 1.5$,these two lines are parallel and never intersect.Therefore,the system of equations has no solution.

Class 11 Mathematics Straight Line Distance between two lines, Perpendicular distance of the line from a point, Position of point w.r.t. line

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The system of equations $x + y = 2$ and $2x + 2y = 3$ will have:

A
Only one solution
B
Many finite solutions
C
No solution
D
None of these

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Distance between two lines, Perpendicular distance of the line from a point, Position of point w.r.t. line

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MediumAP EAMCET 2022

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The positions of the points $(3, 4)$ and $(2, -6)$ with respect to the line $3x - 4y = 8$ are:

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The system of equations $x + y = 2$ and $2x + 2y = 3$ will have:

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The distance between the lines given by $3x + 4y = 9$ and $6x + 8y = 15$ is (in $units$)

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