The equation of a travelling wave on a stretched string of linear mass density $5 \, g/m$ is $y = 0.03 \sin(450t - 9x)$,where distance and time are measured in $SI$ units. The tension in the string is ... $N$.

$A$ $43\, m$ long rope of mass $5.0\, kg$ joins two rock climbers. One climber strikes the rope and the second one feels the effect $1.4\, s$ later. What is the tension in the rope in $N$?

$A$ string of length $L$ is stretched by $\frac{L}{20}$ and the speed of transverse waves along it is $v$. The speed of the wave when it is stretched by $\frac{L}{10}$ will be (assume that Hooke's law is applicable).

$A$ transverse wave propagating on a stretched string of linear density $3 \times 10^{-4} \ kg \ m^{-1}$ is represented by the equation $y = 0.2 \sin (1.5 x + 60 t)$,where $x$ is in metres and $t$ is in seconds. The tension in the string (in newton) is

$A$ steel wire $0.72\; m$ long has a mass of $5.0 \times 10^{-3}\; kg$. If the wire is under a tension of $60\; N$,what is the speed (in $m/s$) of transverse waves on the wire?

If the tension in a wire is made four times,then what will be the change in the speed of the wave propagating in it?