The energy of an electron in a Hydrogen atom | vedclass

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Question

(C) According to Bohr's theory,the energy of an electron in the $n^{th}$ orbit of a Hydrogen atom is given by the formula: $E_n = - \frac{R_H}{n^2} \

Vedclass · Accepted Answer

$E_n = - \frac{1313.3}{n^2} \ kJ \ mol^{-1}$

Vedclass · Answer

(C) According to Bohr's theory,the energy of an electron in the $n^{th}$ orbit of a Hydrogen atom is given by the formula: $E_n = - \frac{R_H}{n^2} \ J \ atom^{-1}$ where $R_H$ is the Rydberg constant for energy,which is approximately $2.18 	imes 10^{-18} \ J$. Converting this to $kJ \ mol^{-1}$: $E_n = - \frac{2.18 	imes 10^{-18} 	imes 6.022 	imes 10^{23}}{n^2} \ J \ mol^{-1} \approx - \frac{1312 \ kJ \ mol^{-1}}{n^2}$. Among the given options,the value closest to the standard constant is $1313.3 \ kJ \ mol^{-1}$.

The energy of an electron in a Hydrogen atom is given by the expression:

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