Electric field at a distance r from an infini | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electric field $E_1$ at a distance $r$ from an infinitely long straight wire with linear charge density $\lambda$ is given by the formula: $E_

Vedclass · Accepted Answer

$E_1 = E_2$

Vedclass · Answer

(C) The electric field $E_1$ at a distance $r$ from an infinitely long straight wire with linear charge density $\lambda$ is given by the formula: $E_1 = \frac{\lambda}{2 \pi \epsilon_0 r} = \frac{2 k \lambda}{r}$,where $k = \frac{1}{4 \pi \epsilon_0}$.The electric field $E_2$ at the centre of a semicircular arc of radius $r$ with linear charge density $\lambda$ is calculated by integrating the field components: $E_2 = \frac{2 k \lambda}{r}$.Comparing the two expressions,we find that $E_1 = \frac{2 k \lambda}{r}$ and $E_2 = \frac{2 k \lambda}{r}$.Therefore,$E_1 = E_2$.

Similar Questions

The electric field at the centre $O$ of a semicircle of radius $a$ having a linear charge density $\lambda$ is given by:

The magnitude of a point charge due to which the electric field $30 \ cm$ away has a magnitude of $2 \ N \ C^{-1}$ is:

Eleven equal point charges,each of magnitude $+Q$,are placed at all the hour positions of a circular clock of radius $r$,except at the $10$ o'clock position. What is the electric field strength at the centre of the clock?

Obtain the equation of electric field at a point due to a system of $n$ point charges.

Two charges $+4e$ and $+e$ are at a distance $x$ apart. At what distance must a charge $q$ be placed from charge $+e$ so that it is in equilibrium?

Vedclass Test Series

Exam Paper Generator

Online Exam Module