The Earth's magnetic field at the equator is | vedclass

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(A) The magnetic field at the equator due to a magnetic dipole is given by the formula: $B_e = \frac{\mu_0 M}{4 \pi R^3}$.Given: $B_e = 0.4 \, G = 0.4

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$1 	imes 10^{23} \, A \cdot m^2$

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(A) The magnetic field at the equator due to a magnetic dipole is given by the formula: $B_e = \frac{\mu_0 M}{4 \pi R^3}$.Given: $B_e = 0.4 \, G = 0.4 	imes 10^{-4} \, T = 4 	imes 10^{-5} \, T$,$R = 6.4 	imes 10^6 \, m$,and $\frac{\mu_0}{4 \pi} = 10^{-7} \, T \cdot m/A$.Substituting the values into the formula:$4 	imes 10^{-5} = 10^{-7} 	imes \frac{M}{(6.4 	imes 10^6)^3}$.$M = \frac{4 	imes 10^{-5} 	imes (6.4 	imes 10^6)^3}{10^{-7}}$.$M = 4 	imes 10^2 	imes (6.4)^3 	imes 10^{18}$.$M = 400 	imes 262.144 	imes 10^{18} \approx 1.05 	imes 10^{23} \, A \cdot m^2$.Thus,the magnetic dipole moment is approximately $1 	imes 10^{23} \, A \cdot m^2$.

The Earth's magnetic field at the equator is approximately $0.4 \, G$. Calculate the Earth's magnetic dipole moment (nearly). (Radius of Earth $R = 6.4 \times 10^6 \, m$)

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