(B) In the nitration of benzene,$H_2SO_4$ acts as a strong acid and $HNO_3$ acts as a base. The reaction between them is: $H_2SO_4 + HO-NO_2 \rightlef

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(B) In the nitration of benzene,$H_2SO_4$ acts as a strong acid and $HNO_3$ acts as a base. The reaction between them is: $H_2SO_4 + HO-NO_2 \rightleftharpoons H_2SO_4^- + H_2O^+-NO_2$ The $H_2O^+-NO_2$ then loses water to form the nitronium ion $(NO_2^+)$,which is the electrophile.