During the thermodynamic process shown in the figure for an ideal gas:

$A$ gas takes part in two processes in which it is heated from the same initial state $1$ to the same final temperature. The processes are shown on the $P-V$ diagram by the straight lines $1-2$ and $1-3$. Points $2$ and $3$ lie on the same isothermal curve. If $Q_1$ and $Q_2$ are the heat transferred along the two processes,then:

An ideal gas is taken around the cycle $ABCA$ as shown in the $P-V$ diagram. The net work done by the gas during the cycle is equal to

An ideal monoatomic gas is taken through the thermodynamic states $A \to B \to C \to D$ via the paths shown in the figure. If $U_A, U_B, U_C$ and $U_D$ represent the internal energy of the gas in states $A, B, C$ and $D$ respectively,then which of the following is not true?

An ideal gas is made to undergo the cyclic process shown in the figure below. Let $\Delta W$ depict the work done,$\Delta U$ be the change in internal energy of the gas,and $Q$ be the heat added to the gas. The signs of each of these three quantities for the whole cycle will be ($0$ refers to no change):

Using the given $P-V$ diagram, the work done by an ideal gas along the path $\text{ABCD}$ is $-$ (in $\text{P}_0 \text{V}_0$)