Due to a force of $(6\hat i + 2\hat j) \text{ N}$,the displacement of a body is $(3\hat i - \hat j) \text{ m}$. The work done is ..... $J$.

$A$ body of mass $m$ accelerates uniformly from rest to a speed $v_0$ in time $t_0$. The work done on the body till any time $t$ is

$A$ force $\vec{F} = (5 \hat{\imath} - 2 \hat{\jmath} + 3 \hat{k}) \text{ N}$ acts on a body of mass $2 \text{ kg}$ and displaces it from position $\vec{r_1} = (3 \hat{\imath} + 2 \hat{\jmath} - \hat{k}) \text{ m}$ to $\vec{r_2} = (6 \hat{\imath} - \hat{\jmath} + 4 \hat{k}) \text{ m}$. The work done is: (in $\text{ J}$)

$A$ force $\vec{F} = 2\hat{i} + b\hat{j} + \hat{k}$ is applied on a particle and it undergoes a displacement $\vec{S} = \hat{i} - 2\hat{j} - \hat{k}$. What will be the value of $b$,if the work done on the particle is zero?

$A$ force $F = (2 \hat{i} + 4 \hat{j}) \text{ N}$ is applied on an object of mass $M$. What is the work done by this force in moving the object horizontally along the $X$-axis by $3 \text{ m}$ (in $\text{ J}$)?

$A$ block of mass $2 \,kg$ is pulled at a constant speed with a taut rope along a frictionless plane that is inclined at $30^{\circ}$. Then the work done by the tension in the rope in pulling it a distance $4 \,m$ along the inclined plane in joule is (acceleration due to gravity $= 10 \,ms^{-2}$)