At what distance for a long straight wire carrying a current of $12\, A$ will the magnetic field be equal to $3 \times 10^{-5} Wb / m ^{2}$ ?
$8 \times 10^{-2} m$
$12 \times 10^{-2} m$
$18 \times 10^{-2} m$
$24 \times 10^{-2} m$
A coil of $12$ turns made by a constant length current carrying wire. If number of turns makes $3$ then change in magnetic field produced at its centre
Two very thin metallic wires placed along $X$ and $Y$-axis carry equal currents as shown here. $AB$ and $CD$ are lines at $45^\circ $ with the axes with origin of axes at $O$. The magnetic field will be zero on the line
A current $I$ flows around a closed path in the horizontal plane of the circle as shown in the figure. The path consists of eight arcs with alternating radii $r$ and $2r$. Each segment of arc subtends equal angle at the common centre $P.$ The magnetic field produced by current path at point $P$ is
The electric current in a circular coil of four turns produces a magnetic induction $32\,T$ at its centre. The coil is unwound and is rewound into a circular coil of single turn, the magnetic induction at the centre of the coil by the same current will be $..........\,T$